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25-12-87/T\SWR09
This website contains an archive of files for the Acorn Electron, BBC Micro, Acorn Archimedes, Commodore 16 and Commodore 64 computers, which Dominic Ford has rescued from his private collection of floppy disks and cassettes.
Some of these files were originally commercial releases in the 1980s and 1990s, but they are now widely available online. I assume that copyright over them is no longer being asserted. If you own the copyright and would like files to be removed, please contact me.
| Tape/disk: | Home » CEEFAX disks » telesoftware4.adl |
| Filename: | 25-12-87/T\SWR09 |
| Read OK: | ✔ |
| File size: | 3B9C bytes |
| Load address: | 0000 |
| Exec address: | FFFFFFFF |
Duplicates
There is 1 duplicate copy of this file in the archive:
- CEEFAX disks » telesoftware4.adl » 25-12-87/T\SWR09
- CEEFAX disks » telesoftware9.adl » 02-09-88/T\SWR09
File contents
Mastering Sideways ROM & RAM - Module 09 - Numerical arguments
--------------------------------------------------------------
In modules 6 and 7 you were shown how to use the MOS to read
numerical arguments by defining new Osbyte and Osword routines. In
this module I will show you one way of reading numerical arguments and
converting them into binary.
There is no one correct way of reading numerical arguments and, as
with most programming problems, there are as many solutions as there
are people to write them. The method I will demonstrate is quite
useful for sideways ram programs because it uses the minimum amount of
user memory and restores that memory after use.
The method demonstrated in this module will read a hexadecimal
argument in the range from &00 to &FFFF and convert the argument into
a two byte binary number. The routine includes range and error
checking to exclude invalid characters. The binary representation of
the argument is stored in two bytes of zero page memory ready to be
used by the rest of the routine. These two bytes can be restored
before returning from the rom.
When you design your SWR programs you should anticipate how they
will be used. If the instructions for using your program tell the user
to enter, for example, the hexadecimal argument one-two-three, your
program should recognise &123 &0123 123 and 0123 as all the same,
correct, argument. Your program should not insist on using leading
zeros or an ampersand (&) prefix if a hexadecimal number is expected
but it should accept them without generating an error.
It is not a good idea to get your SWR program running with a *
command, then prompt for a number and use Osrdch to read it byte after
byte. That style of programming works but it looks very unprofessional
and writing a program which allows the user to edit the number with
the Delete key is quite complicated. The argument(s) should follow the
command so that if, for example, you have written a program which
prints the contents of a memory location and you want to use it to
print the contents of location &900 your SWR interpreter should accept
any of the commands in figure 9.1 to call the routine and print the
answer.
>*PEEK &900 <Return>
>*PEEK &0900 <Return>
>*peek "900" <Return>
>*pe. 0900 <Return>
Figure 9.1 Valid commands and arguments
----------------------------------------
Up to four ASCII characters can be used to represent a two byte
hexadecimal number. The nybble represented by the first ASCII
character depends on how many characters are used to represent the
number. For example, the A in &AB represents the most significant
nybble of the least significant byte but the A in &ABC represents the
least significant nybble of the most significant byte.
If you read the ASCII characters from right to left, instead of the
more natural left to right, the first byte you read will always be the
least significant nybble of the least significant byte. If you read
the characters from left to right you either have to know in advance
how many characters are used so that, if necessary, you can pad out
the number with leading zeros or you have to type the leading zeros to
establish the place value of each character in the argument.
To convert the ASCII representation of a hexadecimal argument into
binary you should start with the least significant nybble of the least
significant byte unless you use an elaborate conversion algorithm or
leading zeros. This presents a problem because the Gsread routine used
to read the ASCII characters from the argument reads from left to
right. To get round this problem you can read each nybble of the
argument, convert it into binary and push it on the stack until you
read the termination character. Then pull each nybble off the stack
and they will be in reverse order, as if they had been read from right
to left.
If you keep a count of the number of nybbles read from the argument
it is a simple matter to pull the nybbles off the stack and convert
each nybble, or pair of nybbles, into a byte. This technique is
illustrated in figure 9.2.
.found
CLC \ terminate with space, return or "
JSR &FFC2 \ initialise argument with Gsinit
LDX #0 \ initial result = &0000
STX &70 \ least sig. byte of result
STX &71 \ most sig. byte of result
DEX \ X will count number of nybbles - 1
.argloop
JSR &FFC5 \ read character from argument with Gsread
BCS endarg \ branch if termination character
CMP #ASC("&") \ is it "&"?
BEQ argloop \ ignore "&"
JSR convert \ convert nybble into binary
PHA \ push nybble on stack
INX \ count nybble in X register
BPL argloop \ branch for next character
.endarg
CPX #4 \ more than 4 characters?
BCS error \ branch if too many
PLA \ pull LS nybble of LS byte
STA &70 \ store as LS byte
DEX \ is that the only nybble?
BMI finish \ branch if it is
PLA \ pull MS nybble of LS byte
ASL A \ shift
ASL A \ left
ASL A \ four
ASL A \ bits
ORA &70 \ OR with &70
STA &70 \ and store LS byte
DEX \ was that the last nybble?
BMI finish \ branch if it was
PLA \ pull LS nybble of MS byte
STA &71 \ store as MS byte
DEX \ was that the last nybble?
BMI finish \ branch if it was
PLA \ pull MS nybble of MS byte
ASL A \ shift
ASL A \ left
ASL A \ four
ASL A \ bits
ORA &71 \ OR with &71
STA &71 \ and store MS byte
.finish
Figure 9.2 Converting from ASCII to binary
-----------------------------------------
After recognising the * command the interpreter will pass control to
the label ".found". The carry flag should be cleared before
initialising the argument so that either a second quotation mark, a
carriage return or a space will be read as the termination character
of the argument.
In figure 9.2 the X register is loaded with zero and then the
content of X is stored in the two consecutive memory locations to be
used for the result. The X register will be used to count the number
of ASCII characters read from the argument minus one. X is decremented
to start with X = &FF when no characters have been read. The argument
is read one character at a time, ignoring any leading ampersand. Each
character is converted from an ASCII character into a binary nybble
and pushed on the stack. The X register is incremented with every
binary nybble pushed on the stack. The routine will keep reading until
the termination character is found.
After reading the termination character the number stored in the X
register should be between 0 and 3 inclusive. If it is outside that
range either too many characters have been included in the argument or
the argument has been omitted. In either case a branch to an error
routine will be made.
When all the characters have been read from the argument the routine
starts pulling the binary nybbles off the stack. The X register is
decremented and tested after each nybble has been processed to see if
that nybble was the first one read from the argument.
There must be at least one nybble to pull off the stack and not more
than four. The first nybble pulled off the stack can be stored in the
memory location reserved for the least significant byte. If a second
nybble is available it has all its bits shifted left four times and
ORed with the first nybble to form the least significant byte. A third
nybble can be stored in the memory location reserved for the most
significant byte and a forth nybble should have all its bits shifted
left four times and ORed with the third nybble to form the most
significant byte.
The result is then available from the two consecutive zero page
memory locations. No other part of user memory or SWR has been used by
the conversion. The error routine and the ASCII character to binary
nybble conversion subroutine are only refered to by name in figure 9.2
but suitable actual routines can be found in the program PEEK.
The program PEEK uses the conversion routine outlined in figure 9.2
to implement the new command *PEEK <hex.number>. To use the program
load the object code it generates into SWR and press the Break key.
You can use the new command to print the hexadecimal value of the
number stored in any byte of the I/O processor's memory. For example,
*PEEK &900, *PEEK 0900 and *PEEK "900" are all equivalent and will all
print the number stored in &900 in the I/O processor's memory.
The program uses a one-command interpreter (lines 300-570) similar
to the ones used in the earlier modules of the course. It uses the
routine in figure 9.2 to read the argument and store the binary
conversion in two zero page bytes (lines 580-1050). The read and
convert routine has been modified slightly to store the two zero page
bytes by pushing them on the stack before making the conversion (lines
610-640). The two bytes can then be restored before returning to the
MOS (lines 1100-1130).
The two zero page bytes are used with post-indexed indirect
addressing to load the accumulator with the byte specified by the
argument (lines 1060-1070). The accumulator content is printed using
the two subroutines in lines 1190-1340. After printing the result the
zero page locations are restored (lines 1100-1130). The registers
pushed on the stack by the interpreter are pulled off to balance the
stack (lines 1140-1160). The accumulator is reset to zero (line 1170)
to inform the other roms that the request has been recognised, and
control is returned to the MOS (line 1180).
The ASCII to binary conversion subroutine is in lines 1350 to 1480.
As well as converting the ASCII character into a binary nybble the
subroutine also checks for valid characters. If an invalid character
is found a branch is made to an error routine (lines 1490-1660)
similar to the one introduced in Module 8.
Because errors can be detected at any stage of the conversion,
restoring the zero page bytes when an error is found would add extra
complications to the error routine. All the information you need to
restore the zero page bytes from the error routine is available in the
X register. If you need the exercise you could modify the error
routine to restore the zero page bytes before printing the error
message. If you do there is no need to balance the stack as well
because it will be reset by BASIC when control passes to the BRK
instruction at &100.
10 REM: PEEK
20 MODE7
30 HIMEM=&3C00
40 DIM save 50
50 diff=&8000-HIMEM
60 address=&70
70 errstack=&100
80 comvec=&F2
90 gsinit=&FFC2
100 gsread=&FFC5
110 osasci=&FFE3
120 osnewl=&FFE7
130 oscli=&FFF7
140 FOR pass = 0 TO 2 STEP 2
150 P%=HIMEM
160 [ OPT pass
170 BRK
180 BRK
190 BRK
200 JMP service+diff
210 OPT FNequb(&82)
220 OPT FNequb((copyright+diff) MOD 256)
230 BRK
240 .title
250 OPT FNequs("PEEK")
260 .copyright
270 BRK
280 OPT FNequs("(C) Gordon Horsington 1987")
290 BRK
300 .service
310 CMP #4
320 BEQ unrecognised
330 RTS
340 .unrecognised
350 PHA
360 TXA
370 PHA
380 TYA
390 PHA
400 LDX #&FF
410 .comloop
420 INX
430 LDA title+diff,X
440 BEQ found
450 LDA (comvec),Y
460 INY
470 CMP #ASC(".")
480 BEQ found
490 AND #&DF
500 CMP title+diff,X
510 BEQ comloop
520 PLA
530 TAY
540 PLA
550 TAX
560 PLA
570 RTS
580 .found
590 CLC
600 JSR gsinit
610 LDA address
620 PHA
630 LDA address+1
640 PHA
650 LDX #0
660 STX address
670 STX address+1
680 DEX
690 .argloop
700 JSR gsread
710 BCS endarg
720 CMP #ASC("&")
730 BEQ argloop
740 JSR convert+diff
750 PHA \ Push hex nybbles
760 INX
770 BPL argloop
780 .endarg
790 CPX #4
800 BCS error
810 PLA \ LS nybble low byte
820 STA address
830 DEX
840 BMI finish
850 PLA \ MS nybble low byte
860 ASL A
870 ASL A
880 ASL A
890 ASL A
900 ORA address
910 STA address \ LS byte
920 DEX
930 BMI finish
940 PLA \ LS nybble high byte
950 STA address+1
960 DEX
970 BMI finish
980 PLA \ MS nybble high byte
990 ASL A
1000 ASL A
1010 ASL A
1020 ASL A
1030 ORA address+1
1040 STA address+1 \ MS byte
1050 .finish
1060 LDY #0
1070 LDA (address),Y
1080 JSR hexbyte+diff
1090 JSR osnewl
1100 PLA
1110 STA address+1
1120 PLA
1130 STA address
1140 PLA
1150 PLA
1160 PLA
1170 LDA #0
1180 RTS
1190 .hexbyte
1200 PHA
1210 LSR A
1220 LSR A
1230 LSR A
1240 LSR A
1250 JSR nybble+diff
1260 PLA
1270 .nybble
1280 AND #&F
1290 SED
1300 CLC
1310 ADC #&90
1320 ADC #&40
1330 CLD
1340 JMP osasci
1350 .convert
1360 CMP #ASC("9")+1
1370 BCS letters
1380 CMP #ASC("0")
1390 BMI error
1400 AND #&F
1410 RTS
1420 .letters
1430 SBC #&37
1440 CMP #&A
1450 BMI error
1460 CMP #&10
1470 BCS error
1480 RTS
1490 .error
1500 LDA #(errormsg+diff) MOD 256
1510 STA address
1520 LDA #(errormsg+diff) DIV 256
1530 STA address+1
1540 LDY #&FF
1550 .errorloop
1560 INY
1570 LDA (address),Y
1580 STA errstack,Y
1590 BPL errorloop
1600 JMP errstack
1610 .errormsg
1620 BRK
1630 BRK
1640 OPT FNequs("Out of range")
1650 BRK
1660 OPT FNequb(&FF)
1670 .lastbyte
1680 ]
1690 NEXT
1700 INPUT'"Save filename = "filename$
1710 IF filename$="" END
1720 $save="SAVE "+filename$+" "+STR$~(HIMEM)+" "+STR$~(las
tbyte)+" FFFF8000 FFFF8000"
1730 X%=save MOD 256
1740 Y%=save DIV 256
1750 *OPT1,2
1760 CALL oscli
1770 *OPT1,0
1780 END
1790 DEFFNequb(byte)
1800 ?P%=byte
1810 P%=P%+1
1820 =pass
1830 DEFFNequw(word)
1840 ?P%=word MOD 256
1850 P%?1=word DIV 256
1860 P%=P%+2
1870 =pass
1880 DEFFNequd(double)
1890 !P%=double
1900 P%=P%+4
1910 =pass
1920 DEFFNequs(string$)
1930 $P%=string$
1940 P%=P%+LEN(string$)
1950 =pass
00000000 4d 61 73 74 65 72 69 6e 67 20 53 69 64 65 77 61 |Mastering Sidewa|
00000010 79 73 20 52 4f 4d 20 26 20 52 41 4d 20 2d 20 4d |ys ROM & RAM - M|
00000020 6f 64 75 6c 65 20 30 39 20 2d 20 4e 75 6d 65 72 |odule 09 - Numer|
00000030 69 63 61 6c 20 61 72 67 75 6d 65 6e 74 73 0d 2d |ical arguments.-|
00000040 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d |----------------|
*
00000070 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 2d 0d 0d 20 |-------------.. |
00000080 20 49 6e 20 6d 6f 64 75 6c 65 73 20 36 20 61 6e | In modules 6 an|
00000090 64 20 37 20 79 6f 75 20 77 65 72 65 20 73 68 6f |d 7 you were sho|
000000a0 77 6e 20 68 6f 77 20 74 6f 20 75 73 65 20 74 68 |wn how to use th|
000000b0 65 20 4d 4f 53 20 74 6f 20 72 65 61 64 0d 6e 75 |e MOS to read.nu|
000000c0 6d 65 72 69 63 61 6c 20 61 72 67 75 6d 65 6e 74 |merical argument|
000000d0 73 20 62 79 20 64 65 66 69 6e 69 6e 67 20 6e 65 |s by defining ne|
000000e0 77 20 4f 73 62 79 74 65 20 61 6e 64 20 4f 73 77 |w Osbyte and Osw|
000000f0 6f 72 64 20 72 6f 75 74 69 6e 65 73 2e 20 49 6e |ord routines. In|
00000100 0d 74 68 69 73 20 6d 6f 64 75 6c 65 20 49 20 77 |.this module I w|
00000110 69 6c 6c 20 73 68 6f 77 20 79 6f 75 20 6f 6e 65 |ill show you one|
00000120 20 77 61 79 20 6f 66 20 72 65 61 64 69 6e 67 20 | way of reading |
00000130 6e 75 6d 65 72 69 63 61 6c 20 61 72 67 75 6d 65 |numerical argume|
00000140 6e 74 73 20 61 6e 64 0d 63 6f 6e 76 65 72 74 69 |nts and.converti|
00000150 6e 67 20 74 68 65 6d 20 69 6e 74 6f 20 62 69 6e |ng them into bin|
00000160 61 72 79 2e 0d 0d 20 20 54 68 65 72 65 20 69 73 |ary... There is|
00000170 20 6e 6f 20 6f 6e 65 20 63 6f 72 72 65 63 74 20 | no one correct |
00000180 77 61 79 20 6f 66 20 72 65 61 64 69 6e 67 20 6e |way of reading n|
00000190 75 6d 65 72 69 63 61 6c 20 61 72 67 75 6d 65 6e |umerical argumen|
000001a0 74 73 20 61 6e 64 2c 20 61 73 0d 77 69 74 68 20 |ts and, as.with |
000001b0 6d 6f 73 74 20 70 72 6f 67 72 61 6d 6d 69 6e 67 |most programming|
000001c0 20 70 72 6f 62 6c 65 6d 73 2c 20 74 68 65 72 65 | problems, there|
000001d0 20 61 72 65 20 61 73 20 6d 61 6e 79 20 73 6f 6c | are as many sol|
000001e0 75 74 69 6f 6e 73 20 61 73 20 74 68 65 72 65 0d |utions as there.|
000001f0 61 72 65 20 70 65 6f 70 6c 65 20 74 6f 20 77 72 |are people to wr|
00000200 69 74 65 20 74 68 65 6d 2e 20 54 68 65 20 6d 65 |ite them. The me|
00000210 74 68 6f 64 20 49 20 77 69 6c 6c 20 64 65 6d 6f |thod I will demo|
00000220 6e 73 74 72 61 74 65 20 69 73 20 71 75 69 74 65 |nstrate is quite|
00000230 0d 75 73 65 66 75 6c 20 66 6f 72 20 73 69 64 65 |.useful for side|
00000240 77 61 79 73 20 72 61 6d 20 70 72 6f 67 72 61 6d |ways ram program|
00000250 73 20 62 65 63 61 75 73 65 20 69 74 20 75 73 65 |s because it use|
00000260 73 20 74 68 65 20 6d 69 6e 69 6d 75 6d 20 61 6d |s the minimum am|
00000270 6f 75 6e 74 20 6f 66 0d 75 73 65 72 20 6d 65 6d |ount of.user mem|
00000280 6f 72 79 20 61 6e 64 20 72 65 73 74 6f 72 65 73 |ory and restores|
00000290 20 74 68 61 74 20 6d 65 6d 6f 72 79 20 61 66 74 | that memory aft|
000002a0 65 72 20 75 73 65 2e 0d 0d 20 20 54 68 65 20 6d |er use... The m|
000002b0 65 74 68 6f 64 20 64 65 6d 6f 6e 73 74 72 61 74 |ethod demonstrat|
000002c0 65 64 20 69 6e 20 74 68 69 73 20 6d 6f 64 75 6c |ed in this modul|
000002d0 65 20 77 69 6c 6c 20 72 65 61 64 20 61 20 68 65 |e will read a he|
000002e0 78 61 64 65 63 69 6d 61 6c 0d 61 72 67 75 6d 65 |xadecimal.argume|
000002f0 6e 74 20 69 6e 20 74 68 65 20 72 61 6e 67 65 20 |nt in the range |
00000300 66 72 6f 6d 20 26 30 30 20 74 6f 20 26 46 46 46 |from &00 to &FFF|
00000310 46 20 61 6e 64 20 63 6f 6e 76 65 72 74 20 74 68 |F and convert th|
00000320 65 20 61 72 67 75 6d 65 6e 74 20 69 6e 74 6f 0d |e argument into.|
00000330 61 20 74 77 6f 20 62 79 74 65 20 62 69 6e 61 72 |a two byte binar|
00000340 79 20 6e 75 6d 62 65 72 2e 20 54 68 65 20 72 6f |y number. The ro|
00000350 75 74 69 6e 65 20 69 6e 63 6c 75 64 65 73 20 72 |utine includes r|
00000360 61 6e 67 65 20 61 6e 64 20 65 72 72 6f 72 0d 63 |ange and error.c|
00000370 68 65 63 6b 69 6e 67 20 74 6f 20 65 78 63 6c 75 |hecking to exclu|
00000380 64 65 20 69 6e 76 61 6c 69 64 20 63 68 61 72 61 |de invalid chara|
00000390 63 74 65 72 73 2e 20 54 68 65 20 62 69 6e 61 72 |cters. The binar|
000003a0 79 20 72 65 70 72 65 73 65 6e 74 61 74 69 6f 6e |y representation|
000003b0 20 6f 66 0d 74 68 65 20 61 72 67 75 6d 65 6e 74 | of.the argument|
000003c0 20 69 73 20 73 74 6f 72 65 64 20 69 6e 20 74 77 | is stored in tw|
000003d0 6f 20 62 79 74 65 73 20 6f 66 20 7a 65 72 6f 20 |o bytes of zero |
000003e0 70 61 67 65 20 6d 65 6d 6f 72 79 20 72 65 61 64 |page memory read|
000003f0 79 20 74 6f 20 62 65 0d 75 73 65 64 20 62 79 20 |y to be.used by |
00000400 74 68 65 20 72 65 73 74 20 6f 66 20 74 68 65 20 |the rest of the |
00000410 72 6f 75 74 69 6e 65 2e 20 54 68 65 73 65 20 74 |routine. These t|
00000420 77 6f 20 62 79 74 65 73 20 63 61 6e 20 62 65 20 |wo bytes can be |
00000430 72 65 73 74 6f 72 65 64 0d 62 65 66 6f 72 65 20 |restored.before |
00000440 72 65 74 75 72 6e 69 6e 67 20 66 72 6f 6d 20 74 |returning from t|
00000450 68 65 20 72 6f 6d 2e 0d 0d 20 20 57 68 65 6e 20 |he rom... When |
00000460 79 6f 75 20 64 65 73 69 67 6e 20 79 6f 75 72 20 |you design your |
00000470 53 57 52 20 70 72 6f 67 72 61 6d 73 20 79 6f 75 |SWR programs you|
00000480 20 73 68 6f 75 6c 64 20 61 6e 74 69 63 69 70 61 | should anticipa|
00000490 74 65 20 68 6f 77 20 74 68 65 79 0d 77 69 6c 6c |te how they.will|
000004a0 20 62 65 20 75 73 65 64 2e 20 49 66 20 74 68 65 | be used. If the|
000004b0 20 69 6e 73 74 72 75 63 74 69 6f 6e 73 20 66 6f | instructions fo|
000004c0 72 20 75 73 69 6e 67 20 79 6f 75 72 20 70 72 6f |r using your pro|
000004d0 67 72 61 6d 20 74 65 6c 6c 20 74 68 65 20 75 73 |gram tell the us|
000004e0 65 72 0d 74 6f 20 65 6e 74 65 72 2c 20 66 6f 72 |er.to enter, for|
000004f0 20 65 78 61 6d 70 6c 65 2c 20 74 68 65 20 68 65 | example, the he|
00000500 78 61 64 65 63 69 6d 61 6c 20 61 72 67 75 6d 65 |xadecimal argume|
00000510 6e 74 20 6f 6e 65 2d 74 77 6f 2d 74 68 72 65 65 |nt one-two-three|
00000520 2c 20 79 6f 75 72 0d 70 72 6f 67 72 61 6d 20 73 |, your.program s|
00000530 68 6f 75 6c 64 20 72 65 63 6f 67 6e 69 73 65 20 |hould recognise |
00000540 26 31 32 33 20 26 30 31 32 33 20 31 32 33 20 61 |&123 &0123 123 a|
00000550 6e 64 20 30 31 32 33 20 61 73 20 61 6c 6c 20 74 |nd 0123 as all t|
00000560 68 65 20 73 61 6d 65 2c 0d 63 6f 72 72 65 63 74 |he same,.correct|
00000570 2c 20 61 72 67 75 6d 65 6e 74 2e 20 59 6f 75 72 |, argument. Your|
00000580 20 70 72 6f 67 72 61 6d 20 73 68 6f 75 6c 64 20 | program should |
00000590 6e 6f 74 20 69 6e 73 69 73 74 20 6f 6e 20 75 73 |not insist on us|
000005a0 69 6e 67 20 6c 65 61 64 69 6e 67 0d 7a 65 72 6f |ing leading.zero|
000005b0 73 20 6f 72 20 61 6e 20 61 6d 70 65 72 73 61 6e |s or an ampersan|
000005c0 64 20 28 26 29 20 70 72 65 66 69 78 20 69 66 20 |d (&) prefix if |
000005d0 61 20 68 65 78 61 64 65 63 69 6d 61 6c 20 6e 75 |a hexadecimal nu|
000005e0 6d 62 65 72 20 69 73 20 65 78 70 65 63 74 65 64 |mber is expected|
000005f0 0d 62 75 74 20 69 74 20 73 68 6f 75 6c 64 20 61 |.but it should a|
00000600 63 63 65 70 74 20 74 68 65 6d 20 77 69 74 68 6f |ccept them witho|
00000610 75 74 20 67 65 6e 65 72 61 74 69 6e 67 20 61 6e |ut generating an|
00000620 20 65 72 72 6f 72 2e 0d 0d 20 20 49 74 20 69 73 | error... It is|
00000630 20 6e 6f 74 20 61 20 67 6f 6f 64 20 69 64 65 61 | not a good idea|
00000640 20 74 6f 20 67 65 74 20 79 6f 75 72 20 53 57 52 | to get your SWR|
00000650 20 70 72 6f 67 72 61 6d 20 72 75 6e 6e 69 6e 67 | program running|
00000660 20 77 69 74 68 20 61 20 2a 0d 63 6f 6d 6d 61 6e | with a *.comman|
00000670 64 2c 20 74 68 65 6e 20 70 72 6f 6d 70 74 20 66 |d, then prompt f|
00000680 6f 72 20 61 20 6e 75 6d 62 65 72 20 61 6e 64 20 |or a number and |
00000690 75 73 65 20 4f 73 72 64 63 68 20 74 6f 20 72 65 |use Osrdch to re|
000006a0 61 64 20 69 74 20 62 79 74 65 20 61 66 74 65 72 |ad it byte after|
000006b0 0d 62 79 74 65 2e 20 54 68 61 74 20 73 74 79 6c |.byte. That styl|
000006c0 65 20 6f 66 20 70 72 6f 67 72 61 6d 6d 69 6e 67 |e of programming|
000006d0 20 77 6f 72 6b 73 20 62 75 74 20 69 74 20 6c 6f | works but it lo|
000006e0 6f 6b 73 20 76 65 72 79 20 75 6e 70 72 6f 66 65 |oks very unprofe|
000006f0 73 73 69 6f 6e 61 6c 0d 61 6e 64 20 77 72 69 74 |ssional.and writ|
00000700 69 6e 67 20 61 20 70 72 6f 67 72 61 6d 20 77 68 |ing a program wh|
00000710 69 63 68 20 61 6c 6c 6f 77 73 20 74 68 65 20 75 |ich allows the u|
00000720 73 65 72 20 74 6f 20 65 64 69 74 20 74 68 65 20 |ser to edit the |
00000730 6e 75 6d 62 65 72 20 77 69 74 68 0d 74 68 65 20 |number with.the |
00000740 44 65 6c 65 74 65 20 6b 65 79 20 69 73 20 71 75 |Delete key is qu|
00000750 69 74 65 20 63 6f 6d 70 6c 69 63 61 74 65 64 2e |ite complicated.|
00000760 20 54 68 65 20 61 72 67 75 6d 65 6e 74 28 73 29 | The argument(s)|
00000770 20 73 68 6f 75 6c 64 20 66 6f 6c 6c 6f 77 20 74 | should follow t|
00000780 68 65 0d 63 6f 6d 6d 61 6e 64 20 73 6f 20 74 68 |he.command so th|
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00003720 20 20 20 20 20 20 20 42 4d 49 20 65 72 72 6f 72 | BMI error|
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00003740 4d 50 20 23 26 31 30 0d 20 31 34 37 30 20 20 20 |MP #&10. 1470 |
00003750 20 20 20 20 20 20 42 43 53 20 65 72 72 6f 72 0d | BCS error.|
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00003770 53 0d 20 31 34 39 30 20 2e 65 72 72 6f 72 0d 20 |S. 1490 .error. |
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00003840 20 49 4e 59 0d 20 31 35 37 30 20 20 20 20 20 20 | INY. 1570 |
00003850 20 20 20 4c 44 41 20 28 61 64 64 72 65 73 73 29 | LDA (address)|
00003860 2c 59 0d 20 31 35 38 30 20 20 20 20 20 20 20 20 |,Y. 1580 |
00003870 20 53 54 41 20 65 72 72 73 74 61 63 6b 2c 59 0d | STA errstack,Y.|
00003880 20 31 35 39 30 20 20 20 20 20 20 20 20 20 42 50 | 1590 BP|
00003890 4c 20 65 72 72 6f 72 6c 6f 6f 70 0d 20 31 36 30 |L errorloop. 160|
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000038e0 20 20 20 20 20 20 20 42 52 4b 0d 20 31 36 34 30 | BRK. 1640|
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00003940 46 46 29 0d 20 31 36 37 30 20 2e 6c 61 73 74 62 |FF). 1670 .lastb|
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00003960 30 20 4e 45 58 54 0d 20 31 37 30 30 20 49 4e 50 |0 NEXT. 1700 INP|
00003970 55 54 27 22 53 61 76 65 20 66 69 6c 65 6e 61 6d |UT'"Save filenam|
00003980 65 20 3d 20 22 66 69 6c 65 6e 61 6d 65 24 0d 20 |e = "filename$. |
00003990 31 37 31 30 20 49 46 20 66 69 6c 65 6e 61 6d 65 |1710 IF filename|
000039a0 24 3d 22 22 20 45 4e 44 0d 20 31 37 32 30 20 24 |$="" END. 1720 $|
000039b0 73 61 76 65 3d 22 53 41 56 45 20 22 2b 66 69 6c |save="SAVE "+fil|
000039c0 65 6e 61 6d 65 24 2b 22 20 22 2b 53 54 52 24 7e |ename$+" "+STR$~|
000039d0 28 48 49 4d 45 4d 29 2b 22 20 22 2b 53 54 52 24 |(HIMEM)+" "+STR$|
000039e0 7e 28 6c 61 73 0d 20 20 20 20 20 20 74 62 79 74 |~(las. tbyt|
000039f0 65 29 2b 22 20 46 46 46 46 38 30 30 30 20 46 46 |e)+" FFFF8000 FF|
00003a00 46 46 38 30 30 30 22 0d 20 31 37 33 30 20 58 25 |FF8000". 1730 X%|
00003a10 3d 73 61 76 65 20 4d 4f 44 20 32 35 36 0d 20 31 |=save MOD 256. 1|
00003a20 37 34 30 20 59 25 3d 73 61 76 65 20 44 49 56 20 |740 Y%=save DIV |
00003a30 32 35 36 0d 20 31 37 35 30 20 2a 4f 50 54 31 2c |256. 1750 *OPT1,|
00003a40 32 0d 20 31 37 36 30 20 43 41 4c 4c 20 6f 73 63 |2. 1760 CALL osc|
00003a50 6c 69 0d 20 31 37 37 30 20 2a 4f 50 54 31 2c 30 |li. 1770 *OPT1,0|
00003a60 0d 20 31 37 38 30 20 45 4e 44 0d 20 31 37 39 30 |. 1780 END. 1790|
00003a70 20 44 45 46 46 4e 65 71 75 62 28 62 79 74 65 29 | DEFFNequb(byte)|
00003a80 0d 20 31 38 30 30 20 3f 50 25 3d 62 79 74 65 0d |. 1800 ?P%=byte.|
00003a90 20 31 38 31 30 20 50 25 3d 50 25 2b 31 0d 20 31 | 1810 P%=P%+1. 1|
00003aa0 38 32 30 20 3d 70 61 73 73 0d 20 31 38 33 30 20 |820 =pass. 1830 |
00003ab0 44 45 46 46 4e 65 71 75 77 28 77 6f 72 64 29 0d |DEFFNequw(word).|
00003ac0 20 31 38 34 30 20 3f 50 25 3d 77 6f 72 64 20 4d | 1840 ?P%=word M|
00003ad0 4f 44 20 32 35 36 0d 20 31 38 35 30 20 50 25 3f |OD 256. 1850 P%?|
00003ae0 31 3d 77 6f 72 64 20 44 49 56 20 32 35 36 0d 20 |1=word DIV 256. |
00003af0 31 38 36 30 20 50 25 3d 50 25 2b 32 0d 20 31 38 |1860 P%=P%+2. 18|
00003b00 37 30 20 3d 70 61 73 73 0d 20 31 38 38 30 20 44 |70 =pass. 1880 D|
00003b10 45 46 46 4e 65 71 75 64 28 64 6f 75 62 6c 65 29 |EFFNequd(double)|
00003b20 0d 20 31 38 39 30 20 21 50 25 3d 64 6f 75 62 6c |. 1890 !P%=doubl|
00003b30 65 0d 20 31 39 30 30 20 50 25 3d 50 25 2b 34 0d |e. 1900 P%=P%+4.|
00003b40 20 31 39 31 30 20 3d 70 61 73 73 0d 20 31 39 32 | 1910 =pass. 192|
00003b50 30 20 44 45 46 46 4e 65 71 75 73 28 73 74 72 69 |0 DEFFNequs(stri|
00003b60 6e 67 24 29 0d 20 31 39 33 30 20 24 50 25 3d 73 |ng$). 1930 $P%=s|
00003b70 74 72 69 6e 67 24 0d 20 31 39 34 30 20 50 25 3d |tring$. 1940 P%=|
00003b80 50 25 2b 4c 45 4e 28 73 74 72 69 6e 67 24 29 0d |P%+LEN(string$).|
00003b90 20 31 39 35 30 20 3d 70 61 73 73 0d | 1950 =pass.|
00003b9c 
25-12-87/T\SWR09.m0
25-12-87/T\SWR09.m1
25-12-87/T\SWR09.m2
25-12-87/T\SWR09.m4
25-12-87/T\SWR09.m5
.